A straight line on a Lambert Conformal Projection chart for normal flight planning purposes ?
Formation > assignment
An aircraft flies a great circle track from 56°N 070°W to 62°N 110°E The total distance travelled is ?
Parallels of latitude on a Direct Mercator chart are ?
The parallels on a lambert conformal conic chart are represented Arcs of concentric circles. the lambert conformal what most of today's aeronautical charts are based on img /com_en/com061 699 jpg . 
Approximately how many nautical miles correspond to 12 cm on a map with a scale of 1 2 000 000 Arcs of concentric circles. 12 cm x 2 000 000 cm = 24 000 000 cm 24 000 000 cm = 240 km 240 km / 1 852 = 130 nm. 
A lambert conformal conic chart has a constant of cone of 0 75 the initial course of a straight line track drawn on this chart from a 40°n 050°w to b 043° t at acourse at b 055° t what the longitude of b Arcs of concentric circles. convergency = 055° 043° = 12° change in longitude = convergency / n change in longitude = 12° / 0 75 = 16° a at 050°w b 34°w (50° 16°) (minus 16° because we are heading east). 
A lambert conformal conic chart has a constant of cone of 0 80 a straight line course drawn on this chart from a 53°n 004°w to b 080° at acourse at b 092° t what the longitude of b Arcs of concentric circles. sin l0 = x / g sin l0 = 0 80 x = 80° 92°= 12° g = 12° / 0 80 = 15° 15° 4° = 11°. Question 161-8
What the radial and dme distance from bel vor/dme n5439 7 w00613 8 to position n5410 w00710 err _a_061 241 Arcs of concentric circles. sin l0 = x / g sin l0 = 0 80 x = 80° 92°= 12° g = 12° / 0 80 = 15° 15° 4° = 11°. Question 161-9
What the radial and dme distance from bel vor/dme n5439 7 w00613 8 to position n5440 w00730 err _a_061 242 Arcs of concentric circles. plot position n5440 w00730 draw a line from belfast vor center your protractor you read 278° img /com_en/com061 242 jpg use latitude scale to find 44 nm. Question 161-10
What the average track °m and distance between wtd ndb n5211 3 w00705 0 and ker ndb n5210 9 w00931 5 err _a_061 244 Arcs of concentric circles. Img /com_en/com061 244 jpg align your protractor with average magnetic north between wtd ker magnetic track 278° use latitude scale to find distance 90 nm. Question 161-11
What the average track °m and distance between crn ndb n5318 1 w00856 5 and wtd ndb n5211 3 w00705 0 err _a_061 246 Arcs of concentric circles. report magnetic north tick from cml clonmel ndb center your protractor you read an average magnetic trak of 142° img /com_en/com061 246 jpg use scale to find distance 95 nm. Question 161-12
What the average track °m and distance between ker ndb n5210 9 w00931 5 and crn ndb n5318 1 w00856 5 err _a_061 248 Arcs of concentric circles. img /com_en/com061 248 png use vertical scale to find distance 70 nm magnetic north indicated over vors ndbs report a magnetic north tick center your protractor you read an average magnetic track of 025°. Question 161-13
On a direct mercator chart at latitude 15°s a certain length represents a distance of 120 nm on earth the same length on chart will represent on earth at latitude 10°n a distance of Arcs of concentric circles. at latitude 15° 120 nm at latitude 10° ? (cos 10 / cos 15)x 120 = 122 3 nm similar solution lenght at equator 120 nm / cos15 = 124 23nm lenght at 10° of latitude 124 23 x cos10 = 122 34. Question 161-14
On a direct mercator chart at latitude 45°n a certain chart length along 45°n represents a distance of 90 nm on surface of earth the same length on a chart along latitude 30°n will represent a distance on earth of Arcs of concentric circles. 60 nm x cos 45 x x = 90 42 42 x x = 90 x = 90 / 42 42 = 2 12 60 x cos 30 x 2 12 = 110 15 nm. Question 161-15
On a transverse mercator chart scale exactly correct along Meridians of tangency. scale correct along meridian of tangency (the central meridian) expands away from it . Question 161-16
On a transverse mercator chart with exception of equator parallels of latitude appear as Meridians of tangency. transverse mercator map of western hemisphere. Question 161-17
An oblique mercator projection used specifically to produce Charts of great circle route between two points. oblique mercator a cylindrical projection based on any other great circle of tangency. Question 161-18
Transverse mercator projections are used Maps of large north/south extent. transverse mercator map of western hemisphere. Question 161-19
On a polar stereographic chart a straight line between a 75° 00'n 166° 00'e and b 78° 00'n 154° 00'e drawn the true track angle of rhumb line in b 317° calculate direction t° of straight line in position a Maps of large north/south extent. the total longitude track change 12° convergency change of longitude x sin mean lat so 12° x sin 77 5 = 11 71° conversion angle half of convergency 11 71/2 = 5 855° 317° + 5 855° = 322 855°. Question 161-20
The scale on a lambert conformal conic chart Is constant along a parallel of latitude. the scale constant along any parallel of latitude at it varies slightly with change of latitude the scale changes along meridians the scale correct along standard parallels the left red distance = center red disance = right red distance the scale constant along a parallel of latitude. Question 161-21
A direct mercator graticule based on a projection that Is constant along a parallel of latitude. the scale constant along any parallel of latitude at it varies slightly with change of latitude the scale changes along meridians the scale correct along standard parallels the left red distance = center red disance = right red distance the scale constant along a parallel of latitude. Question 161-22
On a chart distance along a meridian between latitudes 45°n and 46°n 6 cm the scale of chart approximately Is constant along a parallel of latitude. scale = chart lenght / earth distance scale = 6 cm / 60 nm scale = 6 cm / 111 2 km scale = 6 cm / 11 120 000 cm scale = 1 / 1 853 333. Question 161-23
Given chart scale 1 1 850 000 the chart distance between two points 4 centimetres earth distance approximately Is constant along a parallel of latitude. 4 cm x 1 850 000 cm = 7 400 000 cm = 74 km = 40 nm. Question 161-24
On a mercator chart at latitude 60°n distance measured between w002° and e008° 20 cm the scale of this chart at latitude 60°n approximately Is constant along a parallel of latitude. distance between w002° e008° 10° scale = chart lenght/earth distance earth distance = 10° x 60 nm x cos 60° = 300 nm 300 nm x 1 852 = 555 6 km 1 cm chart scale = 555 6 /20 = 27 78 km 1 cm 2 778 000 cm. Question 161-25
Assume a mercator chart the distance between positions a and b located on same parallel and 10° longitude apart 6 cm the scale at parallel 1 9 260 000 what the latitude of a and b Is constant along a parallel of latitude. scale = chart distance/earth distance = 1/9 260 000 if chart distance = 6 cm earth distance = 6 x 9 260 000cm = 55 560 000 cm 55 560 000 cm = 555 6 km 555 6 / 1 852 = 300 nm 10° of longitude on chart= 300 nm distance = change in longitude (in nm) x cos of latitude 10° at equator = 10° x 60 nm = 600 nm 300 nm = 600 nm x cos of latitude cos of latitude = 300/600 = 0 5 0 5 cos 60º so this at 60ºn or 60°s. Question 161-26
On a lambert chart standard parallels 37°n and 65°n with respect to straight line drawn on map between a n49° w030° and b n48° w040° Great circle rhumb line are to south. with standard parallels at 65°n 37°n parallel of origin will be at 51°n ((65+37)/2) the straight line (n49° to n48°) will be south of parallel of origin the great circle track will be concave to parallel of origin also located south of parallel of origin the rhumb line track will be concave to nearer pole also located south of parallel of origin. Question 161-27
A straight line on a chart 4 89 cm long represents 185 nm the scale of this chart approximately Great circle rhumb line are to south. 185 nm x 1 852 = 342 62 km 342 62 km x 1000 = 342 620 m 342 620 m x 100 = 34 262 000 cm 34 262 000 cm / 4 89 cm = 7 006 544. Question 161-28
At latitude 60°n scale of a mercator projection 1 5 000 000 the length on chart between 'c' n60° e008° and ' n60° w008° Great circle rhumb line are to south. distance on earth = change in longitude x 60 nm x cos latitude 8°e to 8°w = 16° change at 60°n a distance on earth of 16° of longitude is 16° x 60 x cos60° = 480 nm 480 nm = 888 9 km = 88 896 000 cm scale = earth distance /chart distance scale = 88 896 000 cm / 5 000 000cm = 17 78 cm. Question 161-29
The two standard parallels of a conical lambert projection are at n10°40' and n41°20' the cone constant of this chart approximatively Great circle rhumb line are to south. constant of cone (convergency factor) the ratio between top angle of unfolded cone 360° or sine of parallel of origin the parallel of origin about half way between standard parallels midway between n10°40'and n41°20'is n26° sin of 26° = 0 438. Question 161-30
On a direct mercator chart meridians are Parallel equally spaced vertical straight lines. direct mercator chart on a direct mercator chart meridians are parallel equally spaced vertical straight lines rhumb lines or loxodromes are tracks of constant true course. Question 161-31
On which of following chart projections it not possible to represent north or south poles Parallel equally spaced vertical straight lines. direct mercator chart it not possible to represent poles on a direct mercator chart. Question 161-32
Which one of following concerning great circles on a direct mercator chart correct With exception of meridians the equator they are curves concave to equator. direct mercator chart great circles are concave to equator (except meridians the equator itself) concave or convex?! . Question 161-33
On a lambert conformal conic chart distance between parallels of latitude spaced same number of degrees apart Is smaller between standard parallels than outside them. the lambert conformal what most of today's aeronautical charts are based on the parallel of origin midway between two standard parallels where scale will be smallest. Question 161-34
Which one of following statements correct concerning appearance of great circles with exception of meridians on a polar stereographic chart whose tangency at pole The higher latitude closer they approximate to a straight line. . Question 161-35
Which one of following describes appearance of rhumb lines except meridians on a polar stereographic chart Curves concave to pole. . Question 161-36
What the value of convergence factor on a polar stereographic chart Curves concave to pole. on a polar stereographic chart convergency = change of longitude. Question 161-37
A course of 120° t drawn between 'x' 61°30'n and 'y' 58°30'n on a lambert conformal conic chart with a scale of 1 1 000 000 at 60°n the chart distance between 'x' and 'y' Curves concave to pole. distance change in latitude = 3° x 60nm = 180 nm distance between 'x' 'y' = 180 / sin 30°= 360 nm 360 nm x 185200 / 1000000 = 66 67 cm. Question 161-38
Given direct mercator chart with a scale of 1 200 000 at equatorchart length from 'a' to 'b' in vicinity of equator 11 cm what the approximate distance from 'a' to 'b' Curves concave to pole. scale = 1 cm 200 000 cm distance on chart = 11 cm distance on earth = 11 cm x 200 000 = 2 200 000 cm (22 km) 22 / 1 852 = 11 88 nm. Question 161-39
What the radial and dme distance from crk vor/dme n5150 4 w00829 7 to position n5220 w00810 err _a_061 402 Curves concave to pole. img /com_en/com061 402 jpg . Question 161-40
What the radial and dme distance from crk vor/dme n5150 4 w00829 7 to position n5230 w00750 err _a_061 404 Curves concave to pole. img /com_en/com061 404 jpg use vertical scale to find distance magnetic north indicated over vors ndbs.
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